Question

Find the value of
m if the roots of
mx² +2√3x+√3=0 are real and equal​

Answer 1

Answer:

For equal roots D=b

2

−4ac=0

⇒[2(m+1)]

2

−4m(3m+1)=0

⇒m

2

+2m+1−3m

2

−m=0

⇒−2m

2

+m+1=0

⇒2m

2

−m−1=0⇒(m−1)(m+

2

1

)=0

⇒m=1,

2

−1