find the value of m if the zeroes of 6x^2-13x+m=0 are mutually engaged
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Answered by
1
Answer:
6
Step-by-step explanation:
6x
2
−13x+m=0
Let one root=α
Another will be =
α
1
Product of root=
6
m
α×
α
1
=
6
m
m=6.
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