find the value of m, if (x-2) is factor of the polynomial 2x³ -6x² +mx+4 solution
Answers
Answered by
4
Answer:
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Step-by-step explanation:
Let p(x)=2x
3
−6x
2
+5x+a and
g(x)=x−2
=>x−2=0
=>x=2
If g(x) is a factor of p(x), then p(2) should be equal to zero.
p(2)=2x
3
−6x
2
+5x+a=0
=>2(2)
3
−6(2)
2
+5(2)+a=0
=>16−24+10+a=0
=>2+a=0
=>a=−2
Answered by
7
The value of m is 2
Explanation:
Given:
1. (x-2) is a factor
2. polynomial is 2x³ -6x² +mx+4
To find:
The value of m
Step1: Find the x value from the factor
==> The factor is (x-2)
==> x-2 =0
==> x=2
Step2: Find the m value
==>The polunomial is 2x³ -6x² +mx+4 =0
==> Substitute x = 2 in the polynomial
==> 2(2)³ -6(2)² +m(2)+4 =0
==> 2(8)-6(4)+2m+4=0
==> 16-24+2m+4=0
==> 16-20+2m=0
==> -4+2m=0
==> 2m=4
==> m= 4/2
==> m=2
The value of m is 2
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