Question

find the value of m,if (x-2) is the a factor of the polynomial 2x^3-6x^2+MX+4​

Answer 1

Answer:

m=2

Step-by-step explanation:

x-2 is foctor so p(2)=0

p(2)=2(2)^3-6(2)^2+m(2)+4

0=2(8)-6(4)+2m+4

0=16-24+2m+4

0=20-24+2m

-2m=-4

m=-(4)/(-2)

m=2

Answer 2

The value of m = 2

Given :

(x - 2) is the a factor of the polynomial 2x³ - 6x² + mx + 4

To find :

The value of m

Solution :

Step 1 of 2 :

Find zero of the polynomial x - 2

For Zero of the polynomial we have

x - 2 = 0

⇒ x = 2

Step 2 of 2 :

Find the value of m

Let p(x) = 2x³ - 6x² + mx + 4

Since (x - 2) is the a factor of the polynomial 2x³ - 6x² + mx + 4

∴ p(2) = 0

⇒ 2 × 2³ - 6 × 2² + m × 2 + 4 = 0

⇒ 16 - 24 + 2m + 4 = 0

⇒ 2m - 4 = 0

⇒ 2m = 4

⇒ m = 2

Hence the required value of m = 2

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