Question

find the value of m if (x-3) is a factor of x^2-mx-15​

Answer 1

Answer:

given :

(x-3) is factor of x^2-mx-15

To find :

Value of 'm' in the above expression = ?

Solution :

let f(x) = x^2-mx-15 be an polynomial.

we know x-3 is the factor of f(x) . so we can apply factor theorom to find 'm'

1st we have to find the zero of the polynomial.

x-3 = 0

x = 0

so the zero of the polynomial is 3

f (3) = 3^2- m x 3 - 15

f(3) = 9 - 3m -15 =0

f (3) = -6-3m = 0

f(3) = -3m =0

f(3) = m= 6/-3

m = -2

Hence the value of 'm' = -2

hope my answer...thank my answer...

Answer 2

Answer:

hope it's helpful

but

sorry it's not my answer

Step-by-step explanation:

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