find the value of M if X + 4 is a factor of polynomial X square + 3 X +M
Answers
Answered by
12
Hii friend,
X+4 = 0
X = -4
P(X) =0
X²+3X+M = 0
P(-4) = 0
=> (-4)² + 3 × -4 + M
=> 16 -12+M = 0
=> M +4 = 0
=> M = -4
HOPE IT WILL HELP YOU.... :-)
X+4 = 0
X = -4
P(X) =0
X²+3X+M = 0
P(-4) = 0
=> (-4)² + 3 × -4 + M
=> 16 -12+M = 0
=> M +4 = 0
=> M = -4
HOPE IT WILL HELP YOU.... :-)
Answered by
2
Hey!!!
__________
Given,
let p(x) = x² + 3x + m
=> (x + 4) is a factor of p(x)
Then
=> (-4) is a zero of p(x)
=> p(-4) = 0
=> (-4)² + 3(-4) + m = 0
=> 16 - 12 + m = 0
=> 4 + m = 0
=> m = -4
__________
Hope this helps ✌️
__________
Given,
let p(x) = x² + 3x + m
=> (x + 4) is a factor of p(x)
Then
=> (-4) is a zero of p(x)
=> p(-4) = 0
=> (-4)² + 3(-4) + m = 0
=> 16 - 12 + m = 0
=> 4 + m = 0
=> m = -4
__________
Hope this helps ✌️
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