Find the value of m, if x+4 is a factor of the polynomial x²
+3x+m.
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Answer:
x + 4 is a factor of the polynomialx2+3x+m
⟹x2+3x+m≡0(modx+4)
⟹x2+4x−x+m≡0(modx+4)
⟹x(x+4)−x+m≡0(modx+4)
⟹−x+m≡0(modx+4)
⟹x−m≡0(modx+4)
⟹m=−4
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ANSWER ::
The zero of the polynomial x + 4 is given by
x + 4 = 0
= 0So x = - 4
Let f(x) = x² + 3x + m
Now by the Remainder Theorem the required Remainder is
Now by the Remainder Theorem the required Remainder is f( - 4 ) = (-4)² + 3(-4) + m = 16 - 12 + m = m + 4
By the given condition
m + 4 = 0
m = - 4
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