find the value of m if x+6is factor of the polynomial x²+3x+m
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x + 4 is a factor of the polynomialx2+3x+m
⟹x2+3x+m≡0(modx+4)
⟹x2+4x−x+m≡0(modx+4)
⟹x(x+4)−x+m≡0(modx+4)
⟹−x+m≡0(modx+4)
⟹x−m≡0(modx+4)
⟹m=−4
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Answer:
m=-18
Step-by-step explanation:
x+6 is a factor of polynomial x²+3x+m
then, x+6=0
x=-6
polynomial becomes zero when we keep x = -6
x²+3x+m
(-6)²+3(-6)+m=0
36-18+m=0
18+m=0
m=-18
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