Question

find the value of m if (x-m) is a factor of 3x^3 + 2x^2 - 19x + 3m.​

Answer 1

x=m

3m³+2m²-19m+3m=0

3m³+2m²-16m=0

m(3m²+2m-16)=0

m=0

Answer 2

Answer:

m =  0,2 and -8/3

Step-by-step explanation:

 x - m = 0  x = m

GIVEN EQUATION

= 3X^3 +  2X^2 - 19X + 3M

A/Q

= 3(M)^3 + 2(M)^2 - 19(M) +3M = 0

=M{ 3(m)^2 + 2(m) -19 + 3} = 0

m =0 0r 3(m)^2 + 2(m) - 16 = 0

3(m)^2 + 2(m) - 16 = 0

3m^2 + 8m - 6m - 16 = 0

m (3m + 8) - 2 (3m + 8) = 0

(m -2) (3m + 8) = 0

m - 2= 0 and 3m + 8 = 0

m = 2 and m = -8/3

hence m = 0, 2 and -8/3 sine cubic equation has three zeroes

plz................... brainliest