Question

find the value of m in following equation
$4 \times 2 {}^{m + 3} = {8}^{m}$
​

Answer 1

Hello ❤️

$\underline\mathfrak{Answer:-}$

$m = \frac{5}{2}$

$\underline\mathfrak{</strong><strong>Explana</strong><strong>tion</strong><strong>:-}$

$4 \times {2}^{m + 3} = {8}^{m}$

${2}^{2} \times {2}^{m + 3} = {2}^{3m}$

${2}^{2 + m + 3} = {2}^{3m}$

${2}^{5 + m} = {2}^{3m}$

$5 + m = 3m$

$2m = 5$

$m = \frac{5}{2}$

Have a nice night :)