Find the value of m in order that x4 – 2x3 + 3x2 – mx + 5 is exactly divisible by x – 2.
Answers
Answered by
0
Answer:
m=24.5
if I am not wrong..........
Answered by
3
Answer :
The required value of m is '8.5'
Step-by-step explanation :
Given :
x⁴ – 2x³ + 3x² – mx + 5 is exactly divisible by x – 2
To find :
the value of m
Solution :
Let p(x) = x⁴ – 2x³ + 3x² – mx + 5
If the given polynomial x⁴ – 2x³ + 3x² – mx + 5 is exactly divisible by x – 2, then the remainder is zero.
➛ x – 2 = 0
➛ x = +2
By remainder theorem,
If p(x) is divisible by (x - a) , then p(a) = 0
So, when we substitute x = 2, the result is zero.
p(2) = 0
➙ (2)⁴ – 2(2)³ + 3(2)² – m(2) + 5 = 0
➙ 16 - 2(8) + 3(4) - 2m + 5 = 0
➙ 16 - 16 + 12 - 2m + 5 = 0
➙ 12 - 2m + 5 = 0
➙ 17 - 2m = 0
➙ 2m = 17
➙ m = 17/2
➙ m = 8.5
Therefore, the value of m is 8.5
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