Question

find the value of 'm' in order that x⁴-2x³+3x²-mx+5 may be exactly divisble by x-3​

Answer 1

Answer:

19.66....

Step-by-step explanation:

Using the remainder theorem, we take x=3 (since x-3=0).

substituting the value 3 in the equation, we get 81-54+27-3m+5

For x-3 to be a factor of the given equation, the equation with the substituted values should be equal to zero.

81 - 54 + 27 - 3m + 5 = 0

27 + 27 + 5 - 3m = 0

59 - 3m = 0

59 = 3m

m = 59/3

m=19.66...