Question

Find the value of m in terms of variables :)​

Answer 1

Answer:

b=me

m=me

bm=yuo and me

Step-by-step explanation:

a no no te creas pinches pendejos lol

Answer 2

Solution:-

$\large\sf \frac{bl - am}{bm + al} = { \frac{ - a - bm}{b - am} } \\ \\\implies\large\sf( bl - am)(b - am) = ( - a - bm)(bm + al) \\ \implies\large\sf {b}^{2}l \cancel{- blam}\cancel{ - abm} + {a}^{2} {m}^{2} =\cancel{ - abm }- {a}^{2}l - {b}^{2} {m}^{2} \cancel{- bmal } \\ \implies\large\sf b ^{2} l - {a}^{2} {m}^{2} = - {a}^{2} l - {b}^{2} {m}^{2} \\ \implies\large\sf{b}^{2} l + {b}^{2} {m}^{2} + {a}^{2} {m}^{2} + {a}^{2} l = 0 \\\implies\large\sf {b}^{2} l + {a}^{2} l + {m}^{2} ( {b}^{2} + {a}^{2} ) = 0\\\implies\large\sf l( {b}^{2} + {a}^{2} ) = - {m}^{2} ( {b}^{2} + {a}^{2} ) \\\implies\large\sf l = \frac{ - {m}^{2}{{\cancel{( {b}^{2} }+ {a}^{2} )} }} {\cancel{( {b}^{2} + {a}^{2} )} } \\\implies\large\sf l = - {m}^{2} \\\implies\large\sf l + {m}^{2} = 0 \\\implies\large\sf{m}^{2} = - l \\\implies\large\sf m = \sqrt{l} \: i \: \: \\\implies\large\sf (here \:" i" \: is \: an \: imaginary \: number)$