Question

Find the value of m in the expression: [(16)^2m+1 (64)^5]/[(256)^2 * 4] = (256)^3m Please don't make assumption but solve it properly kal exam hai so pls be quick

Answer 1

Answer:

The value of m is 1.

Step-by-step explanation:

[(16)^2m+1 (64)^5]/[(256)^2 * 4] = (256)^3m

$or, \frac{[(16)^{2m+1} (64)^5]}{[(256)^2 * 4]} = (256)^{3m}\\or, \frac{[(16)^{2m} *16*(64)^5]}{[(4^4)^2 * 4]} = (16)^{6m}\\or, \frac{[4^2*(4)^{15}]}{[4^8 * 4]} = \frac{(16)^{6m}}{(16)^{2m}}\\or, \frac{[4^{17}]}{[4^9]} =(16)^{4m}\\ot, 4^8=4^{8m}\\or, 8=8m\\or, m=1 (Ans)$