Question

Find the value of m in the following 6m×6²×6-³= 6¹²​

Answer 1

Answer:

13

Step-by-step explanation:

${6}^{m} \times {6}^{2} \times {6}^{ - 3} = {6}^{12}$

Powers are added when bases are same, then,

${6}^{m + 2 - 3} = {6}^{12}$

${6}^{m - 1} = {6}^{12}$

$m - 1 = 12$

$m = 13$

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