Find the value of m is x2-2mx2+16 is divisible by x+27
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example is given below similarly u can solve ur question:-
By remainder theorem,
x+2=0
x=-2
Therefore,
p(-2)=0
(-2)^3-2m(-2)^2+16=0
-8-8m+16=0
m=1
Hope it helps..
By remainder theorem,
x+2=0
x=-2
Therefore,
p(-2)=0
(-2)^3-2m(-2)^2+16=0
-8-8m+16=0
m=1
Hope it helps..
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