Question

find the value of m , of p(x) =x^3 - 2mx^2 + is 16 is exactly divided by (x+2)​

Answer 1

Answer:

$By \ remainder \ theorem:\\x+2=0\\x=-2$

$p(x)=x^3-2mx^2+16=0$

$p(-2)=(-2)^3-2m(-2)^2+16=0$

$-8-8m+16=0$

$-8m=-8$

$m=8/8$

$m=1$