Question

Find the value of m so that (_4)^2m +1×(_4)^_2=(_4)^3

Answer 1

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$( - 4) {}^{2m + 1} \times ( - 4) {}^{ - 2} = ( - 4) {}^{3}$


$( - 4) {}^{2m + 1} = \frac{( - 4) {}^{3} }{( - 4) {}^{ - ( - 2)} }$


$( - 4) {}^{2m + 1} = ( - 4) {}^{3 - ( - 2)}$


$( - 4) {}^{2m + 1} = ( - 4) {}^{5}$


$2m + 1 = 5$


$2m = 5 - 1$


$2m = 4$


$m = \frac{4}{2}$


$m = 2$


Hope helped