Question

Find the value of m so that quadratic equation MX(x-7)+49=0has two equal roots

Answer 1

for an equation to have equal roots discriminant of this eqn should be zero
$mx(x - 7) + 49 = 0 \\ m {x}^{2} - 7mx + 49 = 0 \\ d = \sqrt{( - 7m) {}^{2} - 4(m)(49)} = 0 \\ 49m {}^{2} = 4m(49) \\ m {}^{2} - 4m = 0 \\ m(m - 4) = 0 \\ m = 0 \: or \: 4$
m can't equal to zero as if m=0 eqn will not remain quad.

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