Question

find the value of m so that the quadratic equation mx(5x-6) =0 has two eq roots?​

Answer 1

Answer:

6/5 ur answer

Step-by-step explanation:

since mx(5x-6)=0

we take two separate parts

mx=0 -----1 & 5x-6-------2

1. x=m

2. 5x-6 =0

6=5x

6/5=x

since x=m and x=6/5

m=6/5

Answer 2

Answer:

value of m = 0

Step-by-step explanation:

Given quadratic equation  $mx(5x-6) = 0$

                                          $5mx^{2} - 6m =0$    

which is in the form of $ax^{2} +bx+ c=0$

                   ⇒ $a=5m$,  $b=0$ and $c=-6m$

and roots of the given equation are equal

                                        Δ = $b^{2} -4ac =0$

                                        Δ =  $(0^{2} )- 4(5m)(-6m)$ =0  

                                              $-20m (-6m) =0$

                                               $120m =0$

                                                   m = 0/120

                                                    m = 0