Question

find the value of m so that the quadratic equation mx(x-7)+49=0 has two equal roots

Answer 1

(mx^2)-(7mx)+49=0;
a=2m;
b=(-7m);
c=49;
discriminant=b^2-4ac;
0=(-7m)*(-7m)-(4*2m*49);
0=(49m^2)-(392);
392+0=(49m^2);
m^2=392/49;
m=✓8;
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Answer 2

Therefore m = 4

Hope this helps you☺️!!