Math, asked by kartikey24, 1 year ago

find the value of m so that the quardatic eq mx(x-7)+49=0 has 2 equal roots

Answers

Answered by mysticd
2
Hi ,

mx( x - 7 ) + 49 = 0

mx² - 7mx + 49 = 0 compare this with

ax² + bx + c = 0 ,

a = m , b = -7m , c = 49

Discreaminant = 0

[ It's given that roots are equal ]

b² - 4ac = 0

( - 7m )² - 4 × m × 49 = 0

49m² - 4 × 49 × m = 0

49m ( m - 4 ) = 0

Therefore ,

m = 0 or m - 4 = 0

m = 0 or m = 4

I hope this helps you.

:)
Similar questions