find the value of m so that the quardatic eq mx(x-7)+49=0 has 2 equal roots
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Hi ,
mx( x - 7 ) + 49 = 0
mx² - 7mx + 49 = 0 compare this with
ax² + bx + c = 0 ,
a = m , b = -7m , c = 49
Discreaminant = 0
[ It's given that roots are equal ]
b² - 4ac = 0
( - 7m )² - 4 × m × 49 = 0
49m² - 4 × 49 × m = 0
49m ( m - 4 ) = 0
Therefore ,
m = 0 or m - 4 = 0
m = 0 or m = 4
I hope this helps you.
:)
mx( x - 7 ) + 49 = 0
mx² - 7mx + 49 = 0 compare this with
ax² + bx + c = 0 ,
a = m , b = -7m , c = 49
Discreaminant = 0
[ It's given that roots are equal ]
b² - 4ac = 0
( - 7m )² - 4 × m × 49 = 0
49m² - 4 × 49 × m = 0
49m ( m - 4 ) = 0
Therefore ,
m = 0 or m - 4 = 0
m = 0 or m = 4
I hope this helps you.
:)
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