Question

find the value of m so that the vectors 3i-2j+kand 2j+ 6i+mk are mutually perpendicular​

Answer 1

Answer:

here is your answer .see........

Step-by-step explanation:

->. ->

let a = 3i+2j+k & b = 6i+2j+mk

Since these two vectors are mutually

-> ->

perpendicular, so a. b =0 i.e.,

=> (3i+2j+k).(6i+2j+mk )=0

=>3×6 + 2×2 + m×1=0

=>18 + 4 + m =0

=>22+m = 0

=> m= -22

hope this helps you ..........

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