Question

find the value of m such that (3^-1+6^-1+9^-1+12^-1)^m=36/25​

Answer 1

Answer:

m = –1

Step-by-step explanation:

${( {3 }^{ - 1} + {6}^{ -1 } + {9}^{ - 1} + {12}^{ - 1} ) }^{m} = \frac{36}{25} \\ = > {( \frac{1}{3} + \frac{1}{6} + \frac{1}{9} + \frac{1}{12} )}^{m} = \frac{36}{25} \\ = > {(\frac{12 + 6 + 4 + 3}{36}) }^{m} = \frac{36}{25} \\ = > { (\frac{25}{36} )}^{m} = \frac{36}{25} \\ = > { (\frac{25}{36} )}^{m} = { (\frac{25}{36} )}^{ - 1} \\ = > m = - 1$

Answer 2

Answer:

m=1

Step-by-step explanation:

jiska answer kisiko nhi aata us prakaar ka question hai