Question

find the value of M such that the lines 3 Xm + 3 Y=5 and Y= 1 - 2 X are perpendicular to each other

Answer 1

Hope u got the required answer

Answer 2

The value of m is

$m =-\dfrac{1}{2}$

Step-by-step explanation:

We are given the following in the question:

$3xm + 3y = 5\\y = 1-2x$

Writing equations in general linear form:

$y = mx + c\\\\y = -\dfrac{3xm}{3} + \dfrac{5}{3}\\\\\text{Line 1: }y = -xm + \dfrac{5}{3}\\\\\text{Line 2: }y = -2x + 1$  

Thus, the slopes of line are:

$m_1 = -m\\m_2 = -2$

Since, the two linear are perpendicular, the product of their slopes is -1.

$m_1\times m_2 = -1\\-m\times -2 = -1\\\\m = -\dfrac{1}{2}$

#LearnMore

The slope of a line is -3. Find the slope of a line that is perpendicular to this line.

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