Question

Find the value of m,when x^7^+m . (x^3)^6m-2/(x)^8m-5= (x^14)^m /(x^3)^6
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Answer 1

Answer:

For equal roots D=b

2

−4ac=0

⇒[2(m+1)]

2

−4m(3m+1)=0

⇒m

2

+2m+1−3m

2

−m=0

⇒−2m

2

+m+1=0

⇒2m

2

−m−1=0⇒(m−1)(m+

2

1

)=0

⇒m=1,

2

−1

Answered By

toppr

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