Question

Find the value of m² + n², if value of m =1, n = -2​

Answer 1

Answer:

The value of $m^{2} + n^{2}$ is 5.

Step-by-step explanation:

Given -

m =1, n = -2​

To find -

The value of $m^{2} + n^{2}$

Solution -

Given equation ,

$m^{2} + n^{2}$

The value of m =1, n = -2​

$m^{2} = 1^{2}$

$m^{2} = 1$

$n^{2} = (-2)^{2}$

Square of negative number is always positive.

$n^{2} = 4$

Put these value of $m^{2} \: and\: n^{2}$ in given equation ,

$m^{2} + n^{2} = 1+4\\m^{2} + n^{2} = 5$

∴ The value of $m^{2} + n^{2}$ is 5.

Answer 2

• As per the data given in the question, we have to find the value of expression.

       Given data:-$m^{2}+n^{2} \ if\ m=1, n=-2.$

       To find:- value of the expression.

        Solution:-

• Here, we will use the below following steps to find a solution using the transposition method:
• Step 1:- we will Identify the variables and constants in the given simple equation.
• Step 2:-then we Simplify the equation in LHS and RHS.
• Step 3:- Transpose or shift the term on the other side to solve the equation further simplest.
• Step 4:- Simplify the equation using arithmetic operation as required that is mentioned in rule 1 or rule 2 of linear equations.
• Step 5:- Then the result will be the solution for the given linear equation.

         By using the transposition method. we get,

           $\Rightarrow m^{2}+n^{2}.$

       So, putting the value of $m\ and \ n$ in above equation, so we get,

            $=(1)^{2}+(-2)^{2}\\=1+4\\=5.$

 Hence, the value will be $5.$