find the value of mentioned angle S is the given circle with centre O
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Step-by-step explanation:
Given that: OA = OC = R
OCA = 48°
since angle OCA = 48°
OA = OC. (Given )
OAC = OCA ( angles opposite to equal sides of a triangle )
OAC = 48°
AOC + OCA + OAC = 180 Degree ( triangle sum property )
AOC = 180 - ( OCA + OAC )
AOC = 180 - ( 48 + 48 )
AOC = 180 - 96
AOC = 84°
since
2 ADC = AOC ( angle subtended by the same arc at the centre is twice angle subtended by the arc at any point on the remaining arc )
ADC = AOC /2
ADC = 84 / 2
ADC = 42°
now, angle subtended by arc ADC at the centre = 360 - 84 = 276°
2 ABC = reflex of AOC
ABC = 276 / 2
ABC = 138°
hence, angle x = ADC = 42°
angle y = ABC = 138°
hope it will help you
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