find the value of middle most term of the a.p -11,-7,-3....49
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Answered by
15
we have
a=-11
d=4
now
an=49
a+(n-1)d = 49
-11 +(n-1)4 = 49
n-1 = 60/4
n-1 =15
n= 16
therefore there are 16 terms in the ap
now
middle term = n/2 and n/2 +1
i.e 8 and 9 th term
now find the 8 and 9 terms using the an formula to get the middle most term of the ap
a=-11
d=4
now
an=49
a+(n-1)d = 49
-11 +(n-1)4 = 49
n-1 = 60/4
n-1 =15
n= 16
therefore there are 16 terms in the ap
now
middle term = n/2 and n/2 +1
i.e 8 and 9 th term
now find the 8 and 9 terms using the an formula to get the middle most term of the ap
jasleenkaur28:
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find the sum of 2 middle most terms of the a.p -4/3,-1,-2/3.......13/3
????
ok ok I m doing wait
given a=-4/3 d=1/3 an=13/3 or a+(n-1)d =13/3 or -4/3 +(n-1)1/3 = 13/3 or n-1=17 or n=18 now middle terms are n/2 and n/2 +1 i.e 9 and 10th term . now using an formula we get a9=4/3 and a10=5/3 . Now a9 + a10 =5/3 + 4/3 = 9/3 =3 therefore the answer is 3 hope it helps and sorry for giving the ans. late
Answered by
10
AP IS -11,-7,-3,....49
here a= -11 d = -7+11= 4
let last term 49 be the nth term
we have
49= -11+(n-1)×4
49=-11+4n-4
49=-15 +4n
49+15 = 4n
64/4 =n
16= n
since there are 16 terms in A.p we get two mid most term I. e 16/2th and 20/2 +1
8th term and 11th term
NOW 8th term = -11+7×4= 17
Now 11th term= -11+10×4 =29
hence, 17 and 29 are middle most term
here a= -11 d = -7+11= 4
let last term 49 be the nth term
we have
49= -11+(n-1)×4
49=-11+4n-4
49=-15 +4n
49+15 = 4n
64/4 =n
16= n
since there are 16 terms in A.p we get two mid most term I. e 16/2th and 20/2 +1
8th term and 11th term
NOW 8th term = -11+7×4= 17
Now 11th term= -11+10×4 =29
hence, 17 and 29 are middle most term
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