Find the value of (n+3)!/n!
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As we know that
n! = n × (n-1) × (n-2) × (n-3)......... 3× 2 × 1
and
(n+3)! =( n+3)× (n+2) × (n+1) × n × (n-1) × (n-2) × (n-3)......... 3× 2 × 1
then (n+3)!/n!
=[ (n+3) × (n+2) × (n+1) × n!]/ n!
= (n+3) × (n+2) × (n+1)
hope it helps
n! = n × (n-1) × (n-2) × (n-3)......... 3× 2 × 1
and
(n+3)! =( n+3)× (n+2) × (n+1) × n × (n-1) × (n-2) × (n-3)......... 3× 2 × 1
then (n+3)!/n!
=[ (n+3) × (n+2) × (n+1) × n!]/ n!
= (n+3) × (n+2) × (n+1)
hope it helps
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