Find the value of n 4(32n+1)=449
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Answered by
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4(32n+1) = 449
32n+1 = 449/4
32n = 449/4-1
32n = 449-4/4
32n = 445/4
n = 445/128
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Answered by
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Answer:
4(32n+1)=449
128n+4=449
128n=449-4
128n=445
n=445/128
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