Question

find the value of n 4(3n+2)-5(6n-1=2(n-8)​

Answer 1

Step-by-step explanation:

$4(3n + 2) - 5(6n - 1) = 2(n - 8)$

$12n + 8 - 30n + 5 = 2n - 16$

$8 + 5 + 16 = 2n - 12n + 30n$

$20n = 29$

$n = \frac{29}{20}$

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Answer 2

Step-by-step explanation:

The terms are n - 2, 4n -1 and 5n + 2.

We know that if a , b and c are in A.P. then \frac{a+c}{2}2a+c =b

i.e. average of a and c is equal to b.

Therefore, by the condition:

\frac{(n-2)+(5n+2)}{2}2(n−2)+(5n+2) =4n - 1.

⇒\frac{n-2+5n+2}{2}2n−2+5n+2 =4n -1

⇒\frac{6n}{2}26n =4n-1

⇒3n=4n-1

⇒4n-3n=1

⇒n=1

Ans:The value of n is 1 and the numbers are 1-2 = -1 , 4*1-1=3 and 5*1+2 = 7 respectively as we see that -1+4=3 and 3+4=7.

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