Question

find the value of n ​

Answer 1

$\frac{2nc3}{nc3} = \frac{11}{1} \\ \frac{2n \: factorial}{3fac \times (2n - 3)fac} = \frac{11}{1} \\ \frac{2n \times 2n - 1 \times 2n - 2 \times 2n - 3 \: fac}{3 \times 2 \times 2n - 3 \: fac} = \frac{11}{1} \\ \frac{2n \times 2n - 1 \times 2n - 2}{6} = \frac{11}{1} \\ 2n \times 2n - 1 \times 2n - 2 = 66$

Solve the eq. And find the value of n

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