Math, asked by Novapride, 1 year ago

Find the value of n.
a) (4/5)^3×(4/5)^-6=(4/5)^2n-1
b) n(3^-5)=3
c) n(-5)^4÷n^2=5
d) 5^10÷5^8=(1/5)^n
e) (-2/3)^4÷(-2/3)^3=(-3/2)^n
f) (-5)^4÷(-5)^2=5^n
Please solve them please,
it will be ok if you don't know how to do other ones but please try to do them all.

Answers

Answered by 8707097291
2
here your 3 answer plese tell me you are setesfi or not
Attachments:
Similar questions