find the value of n for the ap 9 ,18 ,99
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Answer:
a=9 d= a2 -a1
=18-9=9
an=99
therefore
an= a+(n-1)d
99=9+(n-1)9
99-9=(n-1)9
90=(n-1)9
90÷9=n-1
10=n-1
n=10+1
=11
n=11..
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