Math, asked by yuvvanmuthu, 3 months ago

find the value of n for the given gp 2,4,8,16....128​

Answers

Answered by aishunallapati
2

Answer:

n=9

Step-by-step explanation:

a^n = a^(n-1)/r

128 = a^(n-1)/2

a^(n-1)= 256

2^(n-1) = 256=2^8

n-1=8

n=9

Answered by adinarayanayadla
0

Answer:

formula: ar^n-1

 a=2 , r= 2  then n= ?

  2(1)^n-1 = 128

 2^n-1 = 128

2^n-1 = 2^7

n-1 = 7   (bases are equal)

n= 7+1

n = 8

Step-by-step explanation:

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