Find the value of n for which (-1)^n+(-1)^8n=0
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Solution :- (-1)^n +(-1)^8n = 0
i.e., (−1)^n =−1 only when n is odd.
Now, 8n will always be an even integer because
it is a multiple of 2 i.e. (2×4n).
So, (−1)^8n will be equal to 1.
If n is odd, equation will become −1+1=0
So, n has to be Odd Natural Number.
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