find the value of n for which (8n+4),(6n-2) and (2n+7) are in ap
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In AP,difference between successive terms is constant(=d).
So,
(2n+7)-(6n-2)=(6n-2)-(8n+4)
-4n+9=-2n-6
2n=15
n=15/2.
done.
:-)
So,
(2n+7)-(6n-2)=(6n-2)-(8n+4)
-4n+9=-2n-6
2n=15
n=15/2.
done.
:-)
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