find the value of n for which vector a = 2 i + 5 +n K is perpendicular to the vector B =2i-j+k
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Answered by
10
Answer:
Given:
2 vectors are provided:
- 2i + 5j + nk
- 2i - j + k
To find:
Value of "n" for which the vectors are perpendicular to each other.
Concept:
Always remember the fact that for any perpendicular vectors, the dot product (scalar product) is zero.
Calculation:
A . B = 0
=> (2i + 5j + nk)(2i - j + k) = 0
=> 4 - 5 + n = 0
=> n - 1 = 0
=> n = 1
So the value of n = 1.
Answered by
13
Hey!
Good question
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