Question

Find the value of n if
(i) (n + 1)! = 20(n-1)!​

Answer 1

$\underline{ \boxed {\bold {Question}}}$

• Find the value of n if  (n + 1)! = 20(n - 1)!​

$\underline{ \boxed {\bold {Important \: Concepts \: to \: be \: learned}}}$

• In mathematics, the factorial of a positive integer n, denoted by n!, is the product of all positive integers less than or equal to n.

• n! = n × (n - 1) × (n - 2) × (n - 3) .................... × 2 × 1

            = n × (n - 1)!

$\underline{ \boxed {\bold {Answer}}}$

= (n + 1)! = 20 × (n - 1)!

= (n + 1) × (n) × (n - 1)! = 20 × (n - 1)!

= (n + 1) × n = 20

= (n + 1) × n = 5 × 4

$\underline{ \boxed {\bold {\therefore Value \: of \: 'n' \: satisfying = 4}}}$

Hope this helps u..../

【Brainly Advisor】

Answer 2

Answer:

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