find the value of n, if ( n + 1 )! = 12 ( n - 1 )!
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Answer:
(n+1)(n)(n-1)!=12(n-1)!
n²+n-12=0
n²-4n+3n-12=0
n(n-4)+3(n-4)=0
(n+3)(n-4)=0
where n=-3 or 4
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