Find the value of n if
(n+1)!/ (n-1)! = 6
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Hiii....friend,
Here is ur answer,
=> (n+1)! = 6 (n-1)!
=> (n+1)(n)( n-1)! = 6(n-1)!
=> n (n+1) = 6.
=> n = 2.
:-) Hope it helps u.
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