Question

Find the value of n,if n!/2.n-2! and n!/4.n-4! are in the ratio 1:6​

Answer 1

Step-by-step explanation:

n! (n-4)! *4/n! (n-2)!*2 =1/6

2/(n-2)(n-3)= 1/6

n^2-5n+6 = 12

n^2-5n-6=0

(n-6) (n+1)=0

n can take 2 values i.e 6 and -1

as n will be using in factorial we'll consider n=6.