Question

find the value of n if n(n-1)(n-2)=210​

Answer 1

n(n^2-n-2n+2)=210

n(n^2-3n+2)=210

n^3-3n^2+2n=210

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Answer 2

Answer:

n(n-1) (n-2) =210

n(n-1)(n-2) =7*6*5

that means,

n=7

n-1=6

n-2=5