Find the value of 'n' if the sum of the first 'n' terms of an AP 15, 23, 31, .......... is 708 *
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Answered by
3
in the given AP
D=8 (common difference)
THE FIRST TERM IS a=15
s= n/2(2a+ (n-1) d)
708 = n/2 (2×15 + (n-1)8)
1416= n (30 + 8n - 8)
1416= n (22 + 8n)
8n² + 22n - 1416=0
then factorise it and find the value of n
I hope it helps you
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11
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Hey mate,
Step-by-step explanation:
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