Question

find the value of n in each of the f
ollowing
(2/3)_3 ×(2/5)_5 =(2/3)n-2

Answer 1

this is the answer above

Answer 2

Answer:

=10

Step-by-step explanation:

(2/3)^3×(2/3)^5=(2/3)^n-2

(2/3)^3+5=(2/3)^n-2

(2/3)^8=(2/3)n-2 a^b×a^c=a^b+c

8=n-2

n=8+2

n=10

Hope its helpful for you