Question

find the value of n in each of the following (2/3)³×(2/3)5=(2/3)n-2​

Answer 1

Step-by-step explanation:

(8/27)×(10/3) =(2/3)n-2

(242/81)=(2/3)n

(242/81)×(3/2)=n

n=(121/27)

Answer 2

The value of n is 10.

Step-by-step explanation:

Given : Expression $(\frac{2}{3})^3\times (\frac{2}{3})^5=(\frac{2}{3})^{n-2}$

To find : The value of n in each of the following expression ?

Solution :

Expression $(\frac{2}{3})^3\times (\frac{2}{3})^5=(\frac{2}{3})^{n-2}$

Using exponent identity, $a^b\times a^c=a^{b+c}$

$(\frac{2}{3})^{3+5}=(\frac{2}{3})^{n-2}$

$(\frac{2}{3})^{8}=(\frac{2}{3})^{n-2}$

Comparing the base,

$8=n-2$

$n=10$

Therefore, the value of n is 10.

#Learn more

2^n= 512 find the value of n in each of the following​

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