find the value of n in equation is √2^n-2n=0
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Heya User,
--> ( √2 )^n - 2^n = 0
=> ( √2 )^n = ( √2 )^2n
=> n = 2n
=> n = 0 √√
--> ( √2 )^n - 2^n = 0
=> ( √2 )^n = ( √2 )^2n
=> n = 2n
=> n = 0 √√
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