Question

find the value of n in n^2-16n+144=0​

Answer 1

Answer:

n has two values

i.e. 8+4√5

&. 8-4√5

Step-by-step explanation:

$n { }^{2} - 16n + 144 =0$

by quadratic formulae

here,. a= 1

b=-16

c=144

D. =. b^2-4ac

=. (-16)^2-4(1)(144)

=. 256-. 576

=. 320

now

n. =. [ -b +√(D) ]/(2a) & [-b -√D]/(2a)

n. =. [-(-16)+√320]/(2(1)). &. [ -(-16)-√320]/(2(1))

= [ 16+√320]/2 & [ 16-√320 ]/ 2

= [16+8√5]/2. &. [16-8√5]/2

=. 8+4√5 &. 8-4√5