Question

find the value of n in the given expression.
(-3) ^n-3×(-3) ^-3n+1=(-3) ^5​

Answer 1

$\frac{ - 7}{2}$

Step-by-step explanation:

${( - 3)}^{n - 3} \times {( - 3)}^{ - 3n + 1} = {( - 3)}^{5}$

${( - 3)}^{n - 3 - 3n + 1} = {( - 3)}^{5}$

$bases \: are \: same \: so \: powers \: are \\ \: equated$

$n - 3 - 3n + 1 = 5 \\ - 2n - 2 = 5 \\ - 2n = 7 \\ n = \frac{ - 7}{2}$

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